Start/Analysis II/Polarkoordinaten/SteigungAbschnitt 13.1SteigungFalls r=r(θ)r=r(\theta)r=r(θ):LaTeX kopierendydx=r′(θ)sinθ+r(θ)cosθr′(θ)cosθ−r(θ)sinθ.\frac{dy}{dx} =\frac{r'(\theta)\sin\theta+r(\theta)\cos\theta} {r'(\theta)\cos\theta-r(\theta)\sin\theta}.dxdy=r′(θ)cosθ−r(θ)sinθr′(θ)sinθ+r(θ)cosθ.Details ansehen →
Falls r=r(θ)r=r(\theta)r=r(θ):LaTeX kopierendydx=r′(θ)sinθ+r(θ)cosθr′(θ)cosθ−r(θ)sinθ.\frac{dy}{dx} =\frac{r'(\theta)\sin\theta+r(\theta)\cos\theta} {r'(\theta)\cos\theta-r(\theta)\sin\theta}.dxdy=r′(θ)cosθ−r(θ)sinθr′(θ)sinθ+r(θ)cosθ.Details ansehen →