Home/Basic Physics/2D and 3D Motion/Maximum height of a projectile3. 2D and 3D MotionMaximum height of a projectileIn 3. 2D and 3D MotionFormulaCopy LaTeXH=v02sin2θ2gH=\frac{v_0^2\sin^2\theta}{2g}H=2gv02sin2θTagskinematicsphysicsphysics formulamotion 2D 3DprojectilesDetailadditional height with respect to the launch point.Explore the ideaExplore the ideaFound an error? Contact us.Related formulasRelatedTime to maximum heighttmax=v0sinθgt_{\max}=\frac{v_0\sin\theta}{g}tmax=gv0sinθOpen formulaOpen in sectionRelatedMaximum height in vertical launchΔhmax=v022g\Delta h_{\max}=\frac{v_0^2}{2g}Δhmax=2gv02Open formulaOpen in section