Home/Basic Physics/2D and 3D Motion/Projectile — horizontal position3. 2D and 3D MotionProjectile — horizontal positionIn 3. 2D and 3D MotionFormulaCopy LaTeXx=x0+(v0cosθ)tx=x_0+(v_0\cos\theta)tx=x0+(v0cosθ)tTagskinematicsphysicsphysics formulamotion 2D 3DprojectilesDetailHorizontal position of a projectile with zero horizontal acceleration.Explore the ideaExplore the ideaConditionswithout air resistance; ax=0a_x=0ax=0.Found an error? Contact us.Related formulasRelatedInitial velocity components of a projectilev0x=v0cosθ,v0y=v0sinθv_{0x}=v_0\cos\theta,\qquad v_{0y}=v_0\sin\thetav0x=v0cosθ,v0y=v0sinθOpen formulaOpen in sectionRelatedProjectile — vertical positiony=y0+(v0sinθ)t−12gt2y=y_0+(v_0\sin\theta)t-\frac12gt^2y=y0+(v0sinθ)t−21gt2Open formulaOpen in sectionRelatedProjectile — horizontal velocityvx=v0cosθv_x=v_0\cos\thetavx=v0cosθOpen formulaOpen in section