Home/Calculus II/A.4. Exponential and logarithmic integrals/FormulaA.4. Exponential and logarithmic integralsFormulaIn A.4. Exponential and logarithmic integralsFormulaCopy LaTeX∫duu lnu=ln∣lnu∣+C\int \frac{du}{u\,\ln u} = \ln|\ln u| + C∫ulnudu=ln∣lnu∣+CTagsA 4 integrals exponentials and logarithmicDifferential calculusDerivativeDerivative formulaTableVariablesCCCConstante real de integraciónuuuVariable auxiliar de sustitucióndududuDiferencial respecto de uuuln\lnlnNatural logarithmFound an error? Contact us.Related formulasRelatedA.4.2 Logarithms∫lnu du=u lnu−u+C\int \ln u\,du = u\,\ln u - u + C∫lnudu=ulnu−u+COpen formulaOpen in sectionRelatedFormula∫unlnu du=un+1(n+1)2[(n+1)lnu−1]+C\int u^n \ln u\,du = \frac{u^{n+1}}{(n+1)^2}\left[(n+1)\ln u - 1\right] + C∫unlnudu=(n+1)2un+1[(n+1)lnu−1]+COpen formulaOpen in sectionRelatedFormula∫eau cos(bu) du=eaua2+b2(a cos(bu)+b sin(bu))+C\int e^{au}\,\cos(bu)\,du = \frac{e^{au}}{a^2 + b^2}\left(a\,\cos(bu) + b\,\sin(bu)\right) + C∫eaucos(bu)du=a2+b2eau(acos(bu)+bsin(bu))+COpen formulaOpen in sectionRelatedFormula∫umlnnu du=um+1lnnum+1−nm+1∫umlnn−1u du,m≠−1\int u^m \ln^n u\,du = \frac{u^{m+1}\ln^n u}{m+1} - \frac{n}{m+1}\int u^m \ln^{n-1} u\,du, \quad m \neq -1∫umlnnudu=m+1um+1lnnu−m+1n∫umlnn−1udu,m=−1Open formulaOpen in sectionRelatedFormula∫eau sin(bu) du=eaua2+b2(a sin(bu)−b cos(bu))+C\int e^{au}\,\sin(bu)\,du = \frac{e^{au}}{a^2 + b^2}\left(a\,\sin(bu) - b\,\cos(bu)\right) + C∫eausin(bu)du=a2+b2eau(asin(bu)−bcos(bu))+COpen formulaOpen in sectionRelatedFormula∫ln(u2+a2) du=u ln(u2+a2)−2u+2a arctanua+C\int \ln\left(u^2 + a^2\right)\,du = u\,\ln\left(u^2 + a^2\right) - 2u + 2a\,\arctan\frac{u}{a} + C∫ln(u2+a2)du=uln(u2+a2)−2u+2aarctanau+COpen formulaOpen in sectionRelatedFormula∫uneau du=1a uneau−na∫un−1eau du\int u^n e^{au}\,du = \frac{1}{a}\,u^n e^{au} - \frac{n}{a}\int u^{n-1} e^{au}\,du∫uneaudu=a1uneau−an∫un−1eauduOpen formulaOpen in sectionRelatedFormula∫ln∣u2−a2∣ du=u ln∣u2−a2∣−2u+a ln∣u+au−a∣+C\int \ln\left|u^2 - a^2\right|\,du = u\,\ln\left|u^2 - a^2\right| - 2u + a\,\ln\left|\frac{u+a}{u-a}\right| + C∫lnu2−a2du=ulnu2−a2−2u+alnu−au+a+COpen formulaOpen in section